Question

Indicate the equation of the given line in standard form.

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

Answer 1

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Answer 2

First find slope m= (y2-y1)/(x2-x1) =(5-6)/(5+1)=-1/6
Perpendicular slope m1 =-1/m =6
Midpoint of the points ,((x1+x2)/2,(y1+y2)/2) =((-1+5)/2,(6+5)/2) =(2,11/6)
y-y1=m1(x-x1)
(y-(11/6))=6(x-2)
6y-11 =36(x-2)
36x-6y-61=0

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