solve for x (3√x-2)-8=8
\[3\sqrt{x-2}-8=8\]
please show work
\(\normalsize\color{blue}{ 3\sqrt{x-2}-8=8 }\) \(\normalsize\color{blue}{ 3\sqrt{x-2}-8\color{red}{ +8}=8\color{red}{ +8} }\) \(\normalsize\color{blue}{ 3\sqrt{x-2}=16 }\) \(\normalsize\color{blue}{ 3\sqrt{x-2} \color{darkgoldenrod}{ \div3 } =16\color{darkgoldenrod}{ \div3 } }\) \(\normalsize\color{blue}{\sqrt{x-2}=\Large{ \frac{16}{3} }}\)
let me know if you need more help finishing the prob.
@SolomonZelman I need help to finish it.
I did work up to this point but i got stuck right where you where.
square both sides, and you will get \(\normalsize\color{blue}{ x-2=±\frac{\large {256}}{\large {9}} }\) add 2 to both sides \(\normalsize\color{blue}{ x=2±\frac{\large {256}}{\large {9}} }\) you can also do this, ... \(\normalsize\color{blue}{ x=\frac{\large {18}}{\large {9}}±\frac{\large {256}}{\large {9}} }\) \(\normalsize\color{blue}{ x=\frac{\large {18±256}}{\large {9}} }\)
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