Question

3x^2=12x solve for x

Answer 1

\(\normalsize\color{blue}{ 3x^2=12x }\)
\(\normalsize\color{blue}{ 3x^2\color{darkgoldenrod}{-12x}=12x\color{darkgoldenrod}{-12x} }\)
\(\normalsize\color{blue}{ 3x^2-12x=0 }\)
\(\normalsize\color{blue}{ 3x(x^2-4)=0 }\)
\(\normalsize\color{blue}{ 3x(x-2)(x+2)=0 }\)

Answer 2

So
3x=0 or x-2=0 or x+2=0

Answer 3

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Answer 4

\[
3x^2=12x \\
3x^2 - 12x = 0 \\
3x(x-4) = 0 \\
x = 0, 4
\]