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OpenStudy (anonymous):
Solve 3/x-3=x/x-3 - 3/2 for x and determine if the solution is extraneous or not. x = 3, non-extraneous x = 3, extraneous x = -3, extraneous x = -3, non-extraneous
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OpenStudy (jenniferjuice):
3 over "x-3" = x over "x-3" - "3/2" right.?
OpenStudy (jenniferjuice):
if it is the x = 3, extraneous
OpenStudy (anonymous):
yes thats it! thank you so much (:
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