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Algebra
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1. If y varies inversely as x, and y = 4 as x = 8, find y for the x-value of 2. 2.If y varies inversely as x, and y = 3 as x = 8, find y for the x-value of 6.
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\[\large y = \frac{k}{x}\] Will be the formula we will utilize here..varying inversely
When y = 4....x = 8...so \[\large 4 = \frac{k}{8}\] Solving for 'k' we get \[\large k =32\]
If that is true...our formula for this problem will be \[\large y = \frac{32}{x}\] So now...when x = 2...what does 'y' equal?
ok.. this is proportions. so... 1: The answer is Y=0.5 2: The answer is Y=2.25
We would plug in 2 for 'x' and solve for 'y' getting a result of \[\large y = \frac{32}{2} = 16\]
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