Pleaseeeeee help! will fan and medal
Solve the following quadratic trig equations algebraically (without graphing technology) for the domain 0 ≤ x ≤ 360°. Use exact solutions whenever possible.
6cos2(θ) + cos(θ) - 1 = 0
2 - 2sin2(θ) = cos(θ)

Question

Pleaseeeeee help! will fan and medal
Solve the following quadratic trig equations algebraically (without graphing technology) for the domain 0 ≤ x ≤ 360°. Use exact solutions whenever possible. 
6cos2(θ) + cos(θ) - 1 = 0
2 - 2sin2(θ) = cos(θ)

anonymous · Answer

just treat cos $\theta$ as t, so you have 6t^2 +t -1 =0, solve this quadratic to get t, then, plug back cos (theta) =t to solve for (theta). Practice, I can check your work

anonymous · Answer

AWesome thank you! Ill message you with my answer