Question

For sin(θ) = -0.4321, 0 ≤ θ ≤ 360°. (8)
1.How many solutions are possible?
2.In which quadrants would you find the solutions?
3.Determine the reference angle for this equation to the nearest degree.
4.Determine all the solutions to the equation to the nearest degree.

Answer 1

in the entire circle there would be two places

Answer 2

sine is the second coordinate , it is negative in quadrant 3 and 4

Answer 3

you good from there ?

Answer 4

how did you find that?

Answer 5

not sure what you are asking
i didn't find anything, just drew a picture with \(-.4321\) labelled on the y axis

Answer 6

i tried to graph it and it showed up as undefined

Answer 7

that shows you that on the unit circle you should be in quadrant 3 or 4, where sine is negative

Answer 8

if you want the actual value for the angle in degrees you need a calculator, type in \[\sin^{-1}(-.4321)\] and make sure it is set in degree mode
or use wolfram

Answer 9

ohhhhh Okay I got it! thank you! I should have thought of that! haha

Answer 10

i get \(-25.6\)
http://www.wolframalpha.com/input/?i=arcsin%28-.4321%29

Answer 11

then to make sure it is between 0 and 360, add \(360\) to it

Answer 12

that gives you the one on the right hand side

Answer 13

what do you mean add 360?

Answer 14

that gives you 333.5