Question

Suppose now that you wanted to determine the den-sity of a small yellow crystal to confirm that it is sulfur.
From the literature, you know that sulfur has a density
of 2.07 g/cm
3
. How would you prepare 20.0 mL of
the liquid mixture having that density from pure sam-ples of CHCl3and CHBr3? (Note:1 mL = 1 cm
3

Answer 1

what are the densities of the pure samples you're mixing?

Answer 2

CHCL3 (d= 1.492 g/ml) and CHBr3 ( d=2.890)

Answer 3

this was the previous question
Consider the following: you mix 10.0 mL of CHCl3 (d= 1.492 g/mL) and 5.0 mL of CHBr3(d= 2.890g/mL), giving 15.0 mL of solution. What is the density of this mixture?

Answer 4

so you wanna mix these in such a way to get the overall density to 2.07 g/mL

let x be the mL of CHCl3 and y be the mL of CHBr3, then we have:

y+x = 20 mL

1.492x+2.89y=2.07* 20.0 mL


solve these equations

Answer 5

CHCL3= 11.73 mL and CHBr3= 8.268 mL

Answer 6

yep!

Answer 7

thank you! @aaronq

Answer 8

no problem!