Question

HELP!

For sin(θ) = -0.4321, 0 ≤ θ ≤ 360°.
a)How many solutions are possible?
b) In which quadrants would you find the solutions?
c) Determine the reference angle for this equation to the nearest degree.
d) Determine all the solutions to the equation to the nearest degree.

Answer 1

i know in third n fourth quadrunt sin is negative

Answer 2

we know
sin theta=oposit/hypotenuse

Answer 3

2 solutions 3rd and 4rth
may be around (360-26 deg) and 206 deg

Answer 4

@Katieholmes

Answer 5

r u dere @Katieholmes

Answer 6

yes

Answer 7

were u able to solve ???

Answer 8

or do i need 2 xplain?

Answer 9

ummmmm so sin of -.4321= -26 or +26

Answer 10

may i ask u a simple question

Answer 11

so then 180+26 and 360-26 would gif the ref angles?

Answer 12

sure

Answer 13

are u familiar with the curves

Answer 14

no I havent done that yet

Answer 15

ive done a,b and c I just need to know how to solve for d

Answer 16

so then 180+26 and 360-26 are solutions of the equstion are ur answers @Katieholmes

Answer 17

okay awesome thank you

Answer 18

welcome go thru curves :)))