Question

Find $\left[\left(\frac{2}{5}\right)^{12} \left(\frac{3}{16}\right)^{-8}\right] \cdot \left[\left(\frac{2}{5}\right)^{12} \left(\frac{3}{16}\right)^{-8}\right]^{-1}.$

Answer 1

\(\left[\left(\frac{2}{5}\right)^{12} \left(\frac{3}{16}\right)^{-8}\right] \cdot \left[\left(\frac{2}{5}\right)^{12} \left(\frac{3}{16}\right)^{-8}\right]^{-1}.$\)

Answer 2

You mean tht?

Answer 3

yep