Question

Picture of question attached below :)

@phi

Answer 1

First, any idea what quadrant P ends up in ?

Answer 2

P is in quadrant 2 , point P has the coordinates (5, 2) ;
therefore, I believe it would be the opposite- resulting in the coordinates (-5,2) ,
which is option A.

Answer 3

(That is the only logical reasoning I have come up with so far..)

Answer 4

yes. Bute P is (2,5) (not 5,2)

when I do this problem, I change 270 cw to 90 c c w
then I use 90 rotation of (a,b) is (-b,a) or (b,-a)
which we choose depends on which quadrant we want to end up in.
quadrant 2 has negative x and positive y
that means if we start at (2,5) we first swap x and y (5,2)
then because we need to minus the x or y (to make 90º rotation), and we want x negative, we do (-5,2)

Answer 5

oh crap, I switched y and x ; my bad . :/
So you as well have concluded it is A, correct?

Answer 6

yes, you got the correct answer (sometimes it better to be lucky than good!)

Answer 7

Haha, yes! Thanks :)