Question

Medal to please check my answer TY-
In set builder notation,how do you write the solutions of an inequality?

Answer 1

\[-2-x \ge-1\]

Answer 2

not grt at these is it c @phi

Answer 3

@Asevilla5

Answer 4

its d

Answer 5

−2−x≥−1

notice -x can cause trouble. Add +x to both sides
-2 - x + x ≥ -1 + x
-x +x is 0
-2 +0 ≥ -1 + x

and -2 + 0 is just -2

-2 ≥ -1 + x
now add +1 to both sides
1-2 ≥ 1 - 1 + x
which simplifies to
-1 ≥ x
or
x≤ -1 (notice the pointy end always is next to the x when we swap order)

to write the answer you write { } braces, and put an x in them
{ x }
then you add the condition separated by a |
{ x | x≤ -1 }