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OpenStudy (anonymous):
rationalize the denominator: 2+sqroot of 3 / 2- sqroot of 3
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OpenStudy (anonymous):
the awnser is 5
OpenStudy (anonymous):
it's not 5 btw
OpenStudy (anonymous):
oops your right
OpenStudy (anonymous):
first you have to multiply 2-√5 by it's conjugate, which is 2+√5
OpenStudy (anonymous):
can you do that using FOIL?
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OpenStudy (anonymous):
and you multiply the numerator as well by 2+√5
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