Question

How would I find the points for this equation? I've already found the vertex, focus, and directrix.
(y+3)^2=8(x-3)

Answer 1

finding points is easy part .... plug in a "y" value to get an x value, theres a point :)

Answer 2

example
y=0

--> (0+3)^2 = 8(x-3)
--> 9 = 8(x-3)
--> 9/8 = x - 3
--> (9/8) +3 = x

point: (9/8 +3, 0)

and because of symmetry of parabola and y=0 is 3 away from vertex you know another point is
(9/8+3, -6)

Answer 3

Thank you!

Answer 4

yw:)