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Use the distance formula to find the distance between the points (-3,2) and (5,-4) A:10 B:14 C:100 D:12
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(sqr root)(5+3)^2+(-4-2)^2 sqr root of 64+36 sqr root of 100=10 10 is the answer
\[\sqrt{(x2-x1)^2-(y2-y1)^2}\]
So it's 10 .. You guys are sure?
Yeah
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i made a mistake its a "+" sign
The two squares you get in under the radical are 64 and 36, those added are 100, 10 times 10=100
10 is the answer ?
Wait so it's 100?
It's 10
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Okay thanks
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