Question

how do i find the exact solutions to 2sin^2(X)+3sin(x)-2=0

Answer 1

let sin(x)=a and then solve the quadratic.

need more help ?

Answer 2

i dont get it

Answer 3

what about the sin^2(x)
what is that

Answer 4

\(\bf 2{\color{blue}{ sin}}^2(x)+3{\color{blue}{ sin}}(x)-2=0\qquad 2{\color{blue}{ a}}^2+3{\color{blue}{ a}}-2=0\) notice, it's just a quadratic, so you can just factor it, or use the quadratic formula

Answer 5

sin²x becomes a²

Answer 6

(I would just do it, without let this equal that )

Answer 7

(2sinx-1)(sinx+2)

Answer 8

thanks

Answer 9

what about 2sin^2(x)cos(x)=cos(x) on the interval of 0,2pie