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Mathematics 19 Online
OpenStudy (anonymous):

HELP, MEDAL! Eliminate the parameter.

OpenStudy (anonymous):

x=1/2t, y=3t^3-1

OpenStudy (anonymous):

@IMStuck

OpenStudy (anonymous):

@iPwnBunnies

OpenStudy (anonymous):

i got y = 24x^3 - 1

OpenStudy (ipwnbunnies):

Is it x = (1/2)t or x = 1/(2t)

OpenStudy (anonymous):

@iPwnBunnies

OpenStudy (ipwnbunnies):

x = (1/2)t -> t = 2x y = 3t^3 - 1 = 3(2x)^3 - 1 = 3*8x^3 - 1 = 24x^3 - 1 You are correct. :)

OpenStudy (anonymous):

thanks!

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