Question

The probability that a train leaves on time is 0.4. The probability that the train arrives on time and leaves on time is 0.28. What is the probability that the train arrives on time, given that it leaves on time?
@ganeshie8

Answer 1

arrive+leaves=0.28
leaves=0.4

Answer 2

so arrives=0.12

Answer 3

Ok, so I just add them together?

Answer 4

ok so use this.......
Let A = leaves on time
Let B = arrives on time
Thus, A n B arrives on time and leaves on time

P(arrives on time given leaves on time)
= P(B | A)
= P(B n A) / P(A)
= P(A n B) / P(A) .......Hope it helps...........!!