Question

sony purchased a box of chocolates. She ate 20% of them and gave 25% to her friends from the remaining. Again, she ate 20% of it and gave 25% to her friends from the remaining. Then she gave 8 chocolates to a guest. Finally, she is left with 35% of the chocolates that she initially had. How many chocolates did sony eat?

Answer 1

x/5-x=4x/5-->remaining
4x/5-1/4x=11x/20--> remaining

Answer 2

11x/20-x/5=7x/20-->remaining
7x/20-x/4=2x/20--> remaining

Answer 3

2x/20-8=35/100x

Answer 4

or else 11x/20-4x/5=5x/20 remaining

Answer 5

sony purchased a box of chocolates.

Total number of chocolates initially = x

She ate 20% of them and gave 25% to her friends from the remaining.
x(0.8) * (0.75) = y

Again, she ate 20% of it and gave 25% to her friends from the remaining.
y(0.8) * (0.75) = z

Then she gave 8 chocolates to a guest.
z-8 = 35% of x = (0.35)x

Finally, she is left with 35% of the chocolates that she initially had

a percentage of x, z = 0.36, so 36%
giving away 8 chocolate = a drop of 1% of original quantity

==> 8 = 1% of x
so 100% of x = 800

How many chocolates did sony eat?

work through the above, using 800 as x

Answer 6

How many chocolates did sony eat?

work through the above, using 800 as x

x * 0.2 = eaten by sony

+

y * 0.2 = eaten by sony

add the above

Answer 7

how 0.36 %

Answer 8

256 chocolates she ate