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the equation of line AB is y=5x+1.write an equation of a parallel to line AB in slope intercept form that contains point (4,5)
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so..the slope of the line is 5 ( since the form of the eqn is already in the form y=mx+c)..so assume an eqn y=5x+c, that passes through (4,5). So (4,5) should satisfy the eqn.. thats 5=20+c=>c=-15. eqn of line is y=5x-15
@amriju thanks for the help
wecome...:)
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