can someone please please check my work? Will fan and give medal! sin(tan^-1(4/3)) a. the hypotenuse would be 5 b. Angle theta is the angle whose tangent is 4/3 . Find the sine of angle theta. for that i have a hard time understanding
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45 degrees?
now what is sin(theta)?
recall sin(theta)=opp side of theta/hyp
what measurement is for the opp side of theta?
what is the hyp measurement?
all of this is actually already given
sine theta here is 4/5 and my hyp=5
and yes, i do realize that now!
right sin(theta)=4/5
they are basically giving you a way to evaluate sin(tan^-1(4/3))
you know like without a calculator
a. is correct. The actual angle value in degress is not necessary. The sine is 4 over 5.
Sorry, degress should be degrees.
alright, thank you!
Your welcome.
i don't think this was a multiple choice question...
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