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What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6? A. B. C. D.
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Right answer 2x+3y = 5; So normal vector have parellel thus equation of the new line is: 2x +3y = q q determine by point (–2, 3) as q=2*(–2)+3*3=5
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