Question

What are the discontinuities of the function f(x) =x^2-16/4x +24

Answer 1

What are the point(s) where the denominator equals 0?
In other words, what is the solution to 4x + 24 = 0?

Answer 2

x= -24/4?

Answer 3

Yes, or in other words, -6.

Answer 4

is that the discontinuity?

Answer 5

That is a discontinuity.

Answer 6

And there's your answer.

Answer 7

thank you!

Answer 8

\(\bf f(x)=\cfrac{x^2-16}{{\color{brown}{ 4x +24}}}\qquad {\color{brown}{ 4x +24}}=0\qquad \cfrac{x^2-16}{{\color{brown}{ 0}}}\to undefined\)