can someone check if my answer's right? fan and medal!

Without solving, how many solutions does the following equation have? Justify your answer in your written work.
\begin{cases} -4y = -8x^{2}+80x-204 \ y = 2x^{2}+12x+20 \end{cases}

Question

can someone check if my answer's right? fan and medal!

Without solving, how many solutions does the following equation have? Justify your answer in your written work.
\begin{cases} -4y = -8x^{2}+80x-204 \ y = 2x^{2}+12x+20 \end{cases}

anonymous · Answer

-4y = -8x^2 + 90x -204 
y = 2x^2 -20x -51

2x^2-20x-51 = 2x^2 +12x +20
0=32x+71

anonymous · Answer

so how many solutions will this have? :P

anonymous · Answer

2x^2 -20x + 51, not -

0= 32x - 31

one solution.

anonymous · Answer

oh psht haha, thank you so much! :DD

anonymous · Answer

Anytime :)