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Use ΔABC and ΔEDF shown below to answer the question that follows: If and ∠B ≅ ∠D, prove that ΔABC is similar to ΔEDF.
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ac/ef=ab/ed=bc/df
AB/ED = BC/DF
If one angle of a triangle is equal to one angle of other triangle and the corresponding sides including this angle are proportional,then two triangles are similar
@tkhunny
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AB over ED equals BC over DF so their respective angles are equal so, ∠A ≅ ∠E and ∠C ≅ ∠F if all three angles of ΔABC and ΔEDF are equal then ΔABC is similar to ΔEDF
AC/EF=AB/ED = BC/DF
@159507nb .do u need more explanation
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