Question

GUYS, I'M FANNING AND MEDALIN !!!!
PLS HELP!! DESPERATE HERE !!!
Solve the following system of equations algebraically.
\begin{cases} y = 5x^{2}+30x+41 \\ y = 3x^{2}+24x+46 \end{cases}

Answer 1

Let y=y

5x^2 +30x +41= 3x^2 +24x +46
subtract 3x^2 , 24x , 46 over to the left side

2x^2 +6x -5
solve this using quadratic formula

Answer 2

OMG, I LUV YOU SO MUCH <333333 LIFESAVER ;)

Answer 3

\[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a}\]
\[\frac{ -6 \pm \sqrt{36-4(2)(-5)} }{ 2(2)}\]
\[\frac{ -6 \pm \sqrt{76} }{ 4}\]
\[\frac{ -6 \pm 2\sqrt{19} }{ 4}\]
\[\frac{ -3 \pm \sqrt{19} }{ 2}\]

Answer 4

Anytime :)

Answer 5

http://www.ck12.org/algebra/