Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

solve on the interval [0,2pi) 2sin^2x-3x+1=0

OpenStudy (anonymous):

are you sure?

OpenStudy (anonymous):

it cannot be solved maybe any typo??

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!