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PLease can someone show me how to do this: Evaluate: limit/x->1 ...............x^2+5x+4/x^2-1
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sorry.....it is as x approaches -1
\(\Large \frac {(x^2+5x+4)}{(x^2-1)} ~~~\text{as x approaches 1}\) is this ur equation?
yes... i think so
can you factor x^2 +5x+4 ?
yes (x+4)(x+1)
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Oh i can see now.....thanks anyways
yes, x+1 gets cancelled from numerator and denominator :) and welcome ^_^
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