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Mathematics 12 Online
OpenStudy (anonymous):

Augusto wants to prove to his parents that watching TV while he does his homework will help him get better grades. He decides to ask 20 of his friends if they watch TV while they do their homework and what their grades are. He finds that his friends who have high grades also watch TV while they do their homework. He tells his parents that he has proven that watching TV while doing homework will cause his grades to improve. What mistake has Augusto made?

OpenStudy (anonymous):

He did not use a random sample, and he tried to show cause and effect with an observational study. He did not use a random sample, and he tried to show cause and effect with an experiment. He did not separate his friends into different groups, and he didn't apply a treatment. He did not separate his friends into different groups, and he used a survey to collect data.

OpenStudy (anonymous):

He do don't try out his theory himself. It may work for some people but it may not work for him

OpenStudy (anonymous):

That makes sense, but it isn't any of the answer choices. I'm stuck between a and c

OpenStudy (anonymous):

The first one

OpenStudy (anonymous):

I think, I'm sorry

OpenStudy (anonymous):

UGH i hate these questions.. is there anyone you could tag that might know?

OpenStudy (anonymous):

Ummm... I think that the first a is the choice. If I were you I would I pick that one

OpenStudy (anonymous):

Oh ummm...

OpenStudy (anonymous):

Hold on

OpenStudy (anonymous):

Thank you! I just want other people's point of view too, since this isn't something i can do again

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

He also has his email on his profile, so if he isn't online anymore, you can email him

OpenStudy (anonymous):

Thanks :) Can you help with another one?

OpenStudy (anonymous):

Oh nvm i got it!

OpenStudy (anonymous):

Yay! Good for you! I could always help! Just tag me😝😝

OpenStudy (anonymous):

In a study of 235 adults, the mean heart rate was 82 beats per minute. Assume the population of heart rates is known to be approximately normal with a standard deviation of 5 beats per minute. What is the 98% confidence interval for the mean beats per minute? @Samantha1lehman

OpenStudy (anonymous):

I think it's C 80.9 – 86.3 70.9 – 83.3 81.2 – 82.8 80.9 – 83.3

OpenStudy (anonymous):

Okay gimme a second to check back at my notes

OpenStudy (anonymous):

Okay thank you :)

OpenStudy (anonymous):

Yup!! It's C

OpenStudy (anonymous):

thank you!

OpenStudy (anonymous):

Nice job!!

OpenStudy (anonymous):

thanks! I'm still scared to put the answer to the other question, gut feeling

OpenStudy (anonymous):

Hahahahaha, I feel you! Did you ask jim_thompson5910? He knows a lot of answers to questions

OpenStudy (anonymous):

No I didnt, i'm scared that if I email him he won't reply in time! @jim_thompson5910 please answer pleeeeease!!!

OpenStudy (anonymous):

Okay I was looking back at that earlier question, and I think it's A because in the question, it said that the people who got good grades also watch tv while doing homework. Meaning there were people who got good grades and bad grades. He did separate them into those two subgroups. So it has to be A

OpenStudy (anonymous):

Hmmm yeah that makes sense.

OpenStudy (anonymous):

Oh I think he's viewing the question! So lets see

jimthompson5910 (jim_thompson5910):

you're on this one right? "In a study of 235 adults, the mean heart rate was 82 beats per minute. Assume the population of heart rates is known to be approximately normal with a standard deviation of 5 beats per minute. What is the 98% confidence interval for the mean beats per minute?"

OpenStudy (anonymous):

But again, whatever you feel is best Is this for homework?

OpenStudy (anonymous):

No, the first question I asked. But if you can give me your viewpoint on that one too that'd be fine! lol

OpenStudy (anonymous):

Yeah but the class is online so i dont get a do over and i'm on borderline to get a b so I don't wanna go down i'm almost done with the class!

jimthompson5910 (jim_thompson5910):

well first off, he asked his friends and didn't do a random sample so that's a big mistake right there

jimthompson5910 (jim_thompson5910):

he didn't gather a representative sample and the sample is too small

jimthompson5910 (jim_thompson5910):

he also doesn't have a control group so he's definitely not doing an experiment

OpenStudy (anonymous):

So it's an observational?

jimthompson5910 (jim_thompson5910):

yes, you need to have 2 groups (control and experimental) to perform an experiment

OpenStudy (anonymous):

So it's C? or D?

jimthompson5910 (jim_thompson5910):

neither

jimthompson5910 (jim_thompson5910):

there's a much bigger problem: he didn't use a random sample he simply asked his friends this is definitely a biased study

OpenStudy (anonymous):

Wow i'm so confused..... this question seemed so simple :(

jimthompson5910 (jim_thompson5910):

he should have picked more people and picked them more randomly ideally he would pick them out of a hat and more than likely they wouldn't be his friends

OpenStudy (anonymous):

so it's A?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

thank you! Can you help with one more?

jimthompson5910 (jim_thompson5910):

sure

OpenStudy (anonymous):

A survey of 1,200 men and women asked, "Do you earn over $75,000 per year?" The table below shows the responses for males and females:

OpenStudy (anonymous):

Male Female Total Income over $75,000 585 485 1,070 Income below $75,000 65 65 130 Total 650 550 1200

OpenStudy (anonymous):

Based on these data, are "being female" and "earning over $75,000" independent events? No, P(being female | the person earns over $75,000) = P(being female) No, P(being female | the person earns over $75,000) ≠ P(being female) Yes, P(being female | the person earns over $75,000) = P(being female) Yes, P(being female | the person earns over $75,000) ≠ P(being female)

OpenStudy (anonymous):

@jim_thompson5910 Sorry it's messy :/

jimthompson5910 (jim_thompson5910):

what is P(being female) equal to

OpenStudy (anonymous):

Would It be D?

OpenStudy (anonymous):

i'm stuck between d and c

OpenStudy (anonymous):

b*

jimthompson5910 (jim_thompson5910):

what is P(being female) equal to

OpenStudy (anonymous):

the probability?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

you randomly pick a person, what's the chance of them being female?

OpenStudy (anonymous):

550?

OpenStudy (anonymous):

out of 1200

jimthompson5910 (jim_thompson5910):

550/1200 = 0.45833333333333

jimthompson5910 (jim_thompson5910):

now let's focus on just the people making over $75,000 you pick one of those people, what are the chances they are female?

OpenStudy (anonymous):

485/1070

jimthompson5910 (jim_thompson5910):

485/1070 = 0.45327102803739

jimthompson5910 (jim_thompson5910):

so P(being female) = 0.45833333333333 P(being female | earning more than $75,000) = 0.45327102803739

jimthompson5910 (jim_thompson5910):

are they equal?

OpenStudy (anonymous):

no, so they're independent?

jimthompson5910 (jim_thompson5910):

nope, they have to be equal to be independent

jimthompson5910 (jim_thompson5910):

Based on these data, are "being female" and "earning over $75,000" independent events? No, P(being female | the person earns over $75,000) ≠ P(being female)

OpenStudy (anonymous):

So it's b

OpenStudy (anonymous):

cause it can't equal

jimthompson5910 (jim_thompson5910):

basically this tells us that if you earn more than $75,000 then the probability of you being female is altered (or vice versa)

OpenStudy (anonymous):

mmmm, okay I understand now! thank you!

jimthompson5910 (jim_thompson5910):

np

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