The table below represents a linear function f(x) and the equation represents a function g(x):
so what is the equation ?
Part A: y intercept is at point (0,5) y intercept is 5 y intercept means when x = 0, y = a value
for any linear equation the slope intercept form is y = mx + b m is the slope of the line b is the y-intercept, or where the line cuts the y axis
Part B: Average rate of change = \[\large \frac{ f(4)-f(1) }{ 4-1}\] where f(4) means y value at x=4 where f(1) means y value at x=1 can you identify f(4) and f(1)? Tag me if you have questions.
how would i go about trying to find out f(4) and (f1)
Part C: 1. find slope. \[ \large slope= \frac{ y_{2} - y_{1} }{ x_{2} - x_{1}}\] y2= 27 y1= 5 x2= 1 x1=0 Can you plug these number in slope equation, and give me the slope?
Ok , Part B what is y value at x=4?
Look on your chart.
the y value is 93 @study100
good, f(4) = 93 now can you find f(1) ?? = meaning y value at x=1
that would be 27 right @study100
Good, so using the equation \[\frac{ f(4) - f(1) }{ 4-1 }\] We have \[\frac{ 93-27 }{ 3 }\] = 22 This represent how much the displacement changes over the period of time from x=1 hour to x= 4 hours. That's the answer for Part B.
Scroll back to my Part C. post, can you find slope? I have given you the values to plug in.
i found the slope to be 22 is that right? @study100
Good job :) it is! Now using the slope intercept form y= mx + b y= 22x + 5 >>> (from what we know before, b, which is y intercept, is 5.) Problem C tells us the turtle stops at y= 225 miles 225=22x+5 Solve for x. Lemme know if you have x
x=10?
Great job :) The turtle starts at 0. Then it stops at 10 so your domain is from 0 hour to 10 hours. \[0\le x \le 10\] This is your answer for part C.
thank you so much!!!!! i literally only have one more question like this and if you can i would so love your help! @study100
I don't mind :)
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