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Determine the solution set of (x + 1)^2 = 25. {-8, 6} {-8, 4} {-6, 4}
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If you square root both sides, you get x+1=+or-5
Make sense so far?
ya
So, now you have 2 equations. x+1=5 and x+1=-5
Can you solve from there?
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\[(x+1)^2 = 25\] Take the square root on both sides. \[\sqrt{(x+1)^2} = \pm \sqrt{25} = \pm 5\] Why is it \(\pm\) ? Because both \((+5)^2 ~~and~~ (-5)^2\) give 25. So, \[(x+1) = \pm 5\] \[x = \pm 5 - 1\] Getting this? :)
4 an -6
Good job :)
dude long distance high five
*high five :)
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