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Mathematics 13 Online
OpenStudy (anonymous):

If f(x) = x^2 + 1, find f(a + 1)

OpenStudy (anonymous):

a^2+2?

OpenStudy (larseighner):

Try using a+1 in place of x in the function definition.

OpenStudy (larseighner):

No, substitue for x. Leave the contant alone. \[f(something) = (something)^2 + 1\] Just put a+1 in place of the something.

OpenStudy (anonymous):

a^2+ 2a + 2??

OpenStudy (larseighner):

Yes. Exactly.

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