Question

last one please help me
Look at the figure:

Answer 1

If tan x° = 11 divided by r and cos x° = r divided by s, what is the value of sin x°?

sin x° = s divided by 11

sin x° = 11 divided by s

sin x° = 11r

sin x° = 11s

Answer 2

@ganeshie8

Answer 3

@Catseyeglint911

Answer 4

@emmigrace222

Answer 5

someone plis help

Answer 6

@iamabarbiegirl

Answer 7

@ganeshie8 please help

Answer 8

@Catseyeglint911

Answer 9

@Catseyeglint911

Answer 10

sin x° = 11 divided by s

Answer 11

i think it is B?

Answer 12

Remember tan is TOA or opposite over adjacent, so based off the information given, we know that the leg opposite of angle x is 11 and the angle adjacent is 'r'. We can also determine that the hypotenuse is 's' since cos is CAH or adjacent over hypotenuse.

Answer 13

sin x° = 11 divided by s is B isn't it?

Answer 14

ohh now i get it
is D RIGHT?

Answer 15

D. sin x° = 11s is 11 times s which is incorrect. Your first assumption was right.
Let me know if I've confused you.

Answer 16

tan x° = 11 / r
TOA: opposite over adjacent:
11 is the side opposite to angle x
r is the side adjacent to angle x

cos x° = r / s
CAH: adjacent over hypotenuse
r is the side adjacent to angle x (like stated before)
s is the hypotenuse

sin is SOH: opposite over hypotenuse
As we have found...
the angle opposite to angle x is 11
the hypotenuse is s
This means that the sine of angle x = 11/s

Make sense?

Answer 17

yes, i get it
your great