Question

How do I find the domain and range of y= cube root of (1-x^2)?

Answer 1

When x=0, then y=1
when x=1, then y=0
When x = -1, then y=0

so points are: (0,1) (1,0) and (-1,0)

so Domain = {0,1,-1}
and range = {0,1}

I AM NOT SURE WHETHER THIS IS CORRECT>> CHECK WITH OTHERS ALSO

Answer 2

for all other values of x, the value of y becomes Imaginary

Answer 3

The points were correct and the range is y is less than or equal to than 1 because that is it's highest point in the graph and the domain is all real numbers thanks for the help!

Answer 4

my pleasure.. :)