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OpenStudy (anonymous):
Classify the solutions of 3 over x plus 5, plus one fifth, equals 2 over x plus 5 as extraneous or non-extraneous x = -5; extraneous x = -5; non-extraneous x = -10; extraneous x = -10; non-extraneous
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OpenStudy (anonymous):
@radar
OpenStudy (radar):
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