help please fast!!
the best way to find it , is to consider tan theta: |dw:1407650471713:dw|
but i don't know if u havn't studied it.
whats the answer
i can give u the answer but the thing is u won't be able to solve other ones and u'll be confused....in this way,do u still want only the answer ?
yeah just the answer bc this it the only question c: and its an example question
in this way i can't help you....i don't like to give answers...
if u need HELP ... then i'll try my best to help you.
omg please help -.- im on a timer :(
helpp
@PFEH.1999 ???? help plz
ok, remember that slope = tan theta which theta is the angle between the line and the x axis: |dw:1407651036854:dw|
i dont learn about thetas :( yet..
is it B?
so now tan theta is the slope.and you can see that 90<theta<180
no it's not B
is it a negative?
and tan theta = sin theta / cos theta .... so u should know what's sin and cos if 90<theta<180
well find the slope is it positve or negative
yes it's negative ;)
so its A ? ;)
as sin theta is positive and cos theta is negative so positive / negative = negative ;) slope is negative
ty ty
and btw i have no idea what you're saying lol
i know...you were just looking for the answer from the beginning....just notice that it's very bad for u .
is it 3? @PFEH.1999
the points are B(-3,2) and R(3,0) .. slope = yb - yr / xb - xr = 2/-6 = -1/3
you can literally look at the picture and count the rise/run
i said this kind of lines has the slope of negative and u say it's 3 ? :|
whats the answer
@tejasvir heeeeeeeeeelllpppp lol
\( \Large \color){lime}{the points are B(-3,2) and R(3,0) .. slope = yb - yr / xb - xr = 2/-6 = -1/3} \) I said u :)
yes it is A
sry \( \Large \color{lime}{the ~ points ~ are ~ B(-3,2) ~ and ~ R(3,0)~ .. slope ~ = yb - yr / xb - xr = 2/-6 = -1/3} \)
@adoredelano
ty bbyyy :*
Join our real-time social learning platform and learn together with your friends!