Question

**Please help!!

Answer 1

apply the pythagoras theorem

for example No 1:
Hypotenuse 10 , leg 6

Hyp^2 = leg1^2 + leg2^2

10^2 = 6^2 + x^2
x*2 = 10^2 - 6^2 = 100-36 = 64
x = sqrt64 = 8

Answer 2

so thats Leg 8

Answer 3

a^2=b^2+c^2
a-hypotenuse
b-adjacent
c-opposite
(32)^1/2*(32)^1/2+(2)^2=36)^1/2=6