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Mathematics 20 Online
OpenStudy (camerondoherty):

Help?

OpenStudy (camerondoherty):

http://prntscr.com/4bhj9x

OpenStudy (camerondoherty):

For Part A I would say 53

OpenStudy (nincompoop):

where is your solution that shows 53?

OpenStudy (camerondoherty):

Solution?

OpenStudy (nincompoop):

yeh S O L U T I O N

OpenStudy (nincompoop):

lol

OpenStudy (nincompoop):

alright try submitting that and hopefully it is correct since it is a guess

OpenStudy (camerondoherty):

:/

OpenStudy (nincompoop):

how about you plot the values and see what the graph would look like

OpenStudy (camerondoherty):

ok

OpenStudy (nincompoop):

base on the graph, we can obtain the best-fit line and then use that formula to solve for 156

OpenStudy (camerondoherty):

http://prntscr.com/4bhpjp

OpenStudy (camerondoherty):

The Line of best fit equation is y=0.50184911242606x-25.412721893495 Sub x for 156 y=0.50184911242606(156)-25.412721893495?

OpenStudy (camerondoherty):

Then Solve?

OpenStudy (camerondoherty):

Well... I solved for y and i got 52.87 (rounded to the nearest hundreth)

OpenStudy (camerondoherty):

What do you do for part B?

OpenStudy (camerondoherty):

This is the correlation coefficient http://prntscr.com/4bhy1m

OpenStudy (camerondoherty):

Which could be rounded to 1

OpenStudy (camerondoherty):

Now what?

OpenStudy (camerondoherty):

ugh

OpenStudy (nincompoop):

correlation coefficient is the r in your calcuated linear regression, if you don't have that you can use this formula http://mathbits.com/MathBits/TISection/Statistics2/correlation.htm sorry I was doing something else

OpenStudy (camerondoherty):

Lol Thank You c:

OpenStudy (nincompoop):

SO YOU'RE DONE?

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