Help?
For Part A I would say 53
where is your solution that shows 53?
Solution?
yeh S O L U T I O N
lol
alright try submitting that and hopefully it is correct since it is a guess
:/
how about you plot the values and see what the graph would look like
ok
base on the graph, we can obtain the best-fit line and then use that formula to solve for 156
The Line of best fit equation is y=0.50184911242606x-25.412721893495 Sub x for 156 y=0.50184911242606(156)-25.412721893495?
Then Solve?
Well... I solved for y and i got 52.87 (rounded to the nearest hundreth)
What do you do for part B?
Which could be rounded to 1
Now what?
ugh
correlation coefficient is the r in your calcuated linear regression, if you don't have that you can use this formula http://mathbits.com/MathBits/TISection/Statistics2/correlation.htm sorry I was doing something else
Lol Thank You c:
SO YOU'RE DONE?
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