Question

Explain how to find the solution to the system below. Then find the solution(s) to the system. Round answers to the nearest hundredth, if necessary.

y = x^2 - x - 12

y = x

Answer 1

put
\[x=x^2-x-12\] and solve for \(x\) dear

Answer 2

start with
\[x^2-2x-12=0\]

Answer 3

then solve using the quadratic formula or completing the square
you pick

Answer 4

can you hlp me... on it

Answer 5

lets complete the square because \(-2\) is even
\[x^2-2x-12=0\\
x^2-2x=12\\
(x-1)^2=12+1=13\\
x-1=\pm\sqrt{13}\\
x=1\pm\sqrt{13}\]

Answer 6

thanks