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solve by using algebra. please give me a moment to type the equation
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\[\frac{ 1 }{ 2 }\left( x-3 \right)=\frac{ 5 }{ 12 }+\frac{ 2 }{ 3 }\left( 2x-5 \right)\]
whats the LCD?
what denominator do all 3 fractions have in common
none unless you count 1
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so nothing multiplied by 2 or 3 can get to 12?
oh multiply 2 by 6 and 3 by 4
ok so 12 will be the LCD multiply all fractions by 12 to cancel out the fraction 12(x-3)=5+24(2x-5)
distribute 12x-36=5+48x-120 combine like terms 12x-36=48x-115 subtract 12 into 48 -36=36x-115 add 115 into -36 79=36x divide 36 into 79
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