Question

Find the derivative.
(1) y = (x+1/1-x) / (x - 1/x-1)
(2) y = (3x-2) (x-4)/2x-3
(3) s = [(t+3)(t-3)]/t^2-6t+9

Answer 1

is this AB?

Answer 2

it's just the quotient rule for derivatives
(f/g)'=f'g-g'f/g^2

Answer 3

I'm quite confused with number 2