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how many different 5-person basketball teams can a coach choose from among 7 players?
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7 C 5
(combinations)
do I put that in a calculator?
Well, I would just do, \(\LARGE\color{blue}{ 7~C~5= \frac{7!}{5!(7-5)!} }\)
\(\LARGE\color{blue}{ 7~C~5= \frac{7!}{5!(7-5)!}=\frac{7!}{5!\times2!} =\frac{5!\times 6 \times 7}{5!\times2!} }\)
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Can you finish it ?
yes thanks so much!
Anytime !
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