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If the area of a rectangle 24a2b and the length is 8ab2, what would the width of the rectangle, given that width is found by dividing area by length? Simplify the answer. the quantity of 3 times a all over b b over the quantity 3 times a 3 over the quantity a times b 2st
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|dw:1407746114190:dw| \[Area=Length \times Width\] \[Area=24a ^{2}b\] \[Length=8ab ^{2}\] \[24a ^{2}b=8ab ^{2} \times width\] \[\frac{ 24a ^{2}b }{8ab ^{2} }=width\] simplify \[\frac{ 3a }{ b }=width \] \[3ab ^{-1}= width\]
This matches the first choice
whats the answer
thanks
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