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The vertex is located at (–3, 5) and the value of a = –5. Write the vertex form of the equation: a. y = –5(x – 5)^2 – 3 b. y = –5(x – 3)^2 – 5 c. y = 5(x – 5)^2 + 3 d. y = –5(x + 3)^2 +5
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@eric_d @phi
\[f (x) = a(x - h)2 + k\] where (h, k) is the vertex of the parabola
the general form is a(x - b)^2 + c where (b , c) is the coordinates of vertex so put a = -5 , b = = -3 and c = 5
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