Question

Which answer is equal to the quotient in the expression below?

(6x^6 - 6x^3 - 9x^2 + 3x) / (3x)

A. 2x^3 - 2x^2 + 2x - 3
B. 2x^3 + 2x^2 + 2x
C. 2x^5 - 2x^2 - 3x + 1
D. 2x^3 - 2x^2 - 3x - 2

Answer 1

\[\frac{ 6x ^{6}-6x ^{3}-9x ^{2}+3x }{ 3x }\]
factorize the numerator
\[\frac{ 3x(2x ^{5}-2x ^{2}-3x+1) }{ 3x }\]
the 3x cancel each other and you remain with
\[2x ^{5}-2x ^{2}-3x+1\]

Answer 2

that is choice C

Answer 3

x^2-4-3(x-2)

Answer 4

\[x ^{2}-4-3(x-2)=x ^{2}-4-3x+6\]
\[x ^{2}+2-3x=(x-2)(x-1)\]

Answer 5

@sieunhangao

Answer 6

3x(x-7)+2x-14=0

Answer 7

\[3x(x-7)+2x-14=0\]
\[3x ^{2}-21x+2x-14=0\]
\[3x ^{2}-19x-14=0\]

Answer 8

lam sao nua

Answer 9

meaning

Answer 10

nghia la sao
chi lun phan dap so di nha

Answer 11

chi dum di

Answer 12

English?

Answer 13

tieng anh la sao

Answer 14

nang ni pn chi minh lun phan tiep theo di

Answer 15

hiu hu

Answer 16

Tôi không nói được tiếng việt

Answer 17

my next problem is to ask now

Answer 18

3x(x-7)+2x-14=0

Answer 19

\[3x(x-7)+2x-14=0\]
First open up the brackets
\[3x ^{2}-21x+2x-14=0\]
Add the like terms
\[3x ^{2}-20x-14=0\]
What do you want to do?

Answer 20

lam sao

Answer 21

tim x

Answer 22

nhanh len

Answer 23

làm những gì bạn muốn làm với các phương trình?
Bạn đã không được hướng dẫn

Answer 24

@Mokeira the first time is correct the second time has an error -21 + 2 = 19 @sieunhangao the method is correct I hope you understand now.

Answer 25

a^3b-ab^3+a^2+2ab+b^2

Answer 26

giup toi bai do voi

Answer 27

a^3b-ab^3+a^2+2ab+b^2