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OpenStudy (anonymous):
Simplify: (sin Θ − cos Θ)2 + (sin Θ + cos Θ)2
1
2
sin2 Θ
cos2 Θ
@Gin_Ichimaru @dan815 @zuberbier120 @amistre64 @love_jessika15 @YanaSidlinskiy
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OpenStudy (anonymous):
2
OpenStudy (anonymous):
2
OpenStudy (solomonzelman):
(sin Θ − cos Θ)² + (sin Θ + cos Θ)²
applying ` (a-b)²=a²-2ab+b² ` and ` (a+b)²=a²+2ab+b²`
sin²Θ + 2sinΘcosΘ− cos Θ² + sin²Θ - 2sinΘcosΘ− cos Θ²
2sin²Θ − 2cos Θ²
OpenStudy (solomonzelman):
My bad, yes it is a 2
OpenStudy (solomonzelman):
the are positive.
sin²Θ + 2sinΘcosΘ+ cos Θ² + sin²Θ - 2sinΘcosΘ+ cos Θ²
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OpenStudy (anonymous):
ok thank you
OpenStudy (solomonzelman):
the only thing is that you just posted a plain answer, but other than that...
OpenStudy (anonymous):
its two don't let him run u in circles she just wants the answer
OpenStudy (solomonzelman):
Good work, but if someone wants just the answer, it is not a reason to violate the rule.
OpenStudy (solomonzelman):
\[\prod_{ }^{ }\sum_{ }^{ }\Huge{\times }t~~~ti me,~~~I'l l ~~~report.\]
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OpenStudy (anonymous):
what rule u nerd
OpenStudy (yanasidlinskiy):
Calling someone a nerd? You've agreed to the CoC not to be rude:)
OpenStudy (anonymous):
coc??
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