Question

27 a to the 9th power b all over negative 9 a squared b =

Answer 1

\[\frac{27a^9b}{-9a^2b}\]

the rule for dividing is subtract the powers....\[\frac{x^a}{x^b} = x^{a - b}\]

so look at it in parts

numbers, letters powers

\[\frac{27}{-9} \times \frac{a^9}{a^2} \times \frac{b}{b} = \]

hope it helps

Answer 2

thanks you so much