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How to integrate (1+(x-1)sec^2 x)/(x-1)?
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split the fraction
How?
(a+b)/c = a/c + b/c ....
or in this case: (a+cb)/c = a/c + b
I got it.
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\[\int\frac{1}{x-1}+sec^2(x)~dx\]
Why didn't I thought of that before?
:)
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