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evaluate each function at x=5/3. f(x)=x^2+3-2 explain
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i am guessing there is a typo here and it is really \[f(x)=x^2+3x-2\]
yes thats it
In other words, evaluate \(f\left(\frac{5}{3}\right)\)
yes
Okay so \(f\left(\dfrac{5}{3}\right) = \left(\dfrac{5}{3}\right)^2 + 3\left(\dfrac{5}{3}\right) -2 \)
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Can you simplify: \(\left(\dfrac{5}{3}\right)^2 + 3\left(\dfrac{5}{3}\right) -2\)
nope
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