Question

1 find the least number between 200 and 500 which leaves a reminder of 3 in each case when devided by 8,10,12 and 30

Answer 1

steps
1. 8 = \[2^{3}\],
10 = 2*5,
12 = 2^2*3,
18 = 2 *3^2
the all divide
2^3 *3^2*5 = 360
363 is least number in 200 to 500
there is a remainder 3 in each case
3 +360 = 363

Answer 2

got me? :)

Answer 3

let our number be G
G mod 8=3
G mod 10=3
G mod 12 =3
G mod 30 = 3